-1.5x^2+1.69x+18=0

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Solution for -1.5x^2+1.69x+18=0 equation:



-1.5x^2+1.69x+18=0
a = -1.5; b = 1.69; c = +18;
Δ = b2-4ac
Δ = 1.692-4·(-1.5)·18
Δ = 110.8561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.69)-\sqrt{110.8561}}{2*-1.5}=\frac{-1.69-\sqrt{110.8561}}{-3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.69)+\sqrt{110.8561}}{2*-1.5}=\frac{-1.69+\sqrt{110.8561}}{-3} $

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